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Q.

A particle moves towards east with velocity 5 m/s. After 10 seconds its direction changes towards north with same velocity. The average acceleration of the particle is

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a

Zero

b

12m/s2N-W

c

12m/s2N-E

d

12m/s2S-W

answer is B.

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Detailed Solution

∆v = 2vsin(θ2)  = 2×5×sin450 = 102∴  a = ∆v∆t= 10210 = 12m/s2
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A particle moves towards east with velocity 5 m/s. After 10 seconds its direction changes towards north with same velocity. The average acceleration of the particle is