A particle moves under the action of a force F→=20i^+15j^ along a straight line 3y+αx=5 where α is a constant. If the work done by the force is zero. Then the value of α is…..
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a
49
b
94
c
3
d
4
answer is D.
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Detailed Solution
Slope of direction of F→=m1=1520 ---(1)Slope of direction of S→=m2=−α3---(2)∴F→=perpendicular to s→⇒m1m2=−1from (1) and (2) we get α=4