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Q.

A particle moves with constant acceleration along a straight line starting from rest. The percentage increase in the displacement during the 4th sec compared to that in the 3rd sec is…

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a

30%

b

70%

c

40%

d

60%

answer is C.

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Detailed Solution

Given       u=0 n1=3 n2=4From the equation  sn=u+an−12s3=a3−12=5a2s4=a4−12=7a2The percentage increase in the 4th sec s=s4−s3s3×100%=7a2−5a25a2×100=25×100 =40%.
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