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A particle moves with constant speed along a circular path of radius 1m. Time period of revolution of the particle is 2 sec. Then magnitude of average velocity of the particle when it moves from one point to the diametrically opposite point is

a
π m/s
b
2 m/s
c
2 π m/s
d
2.5 m/s

detailed solution

Correct option is B

Displacement  =2r=2×1m=2mTime taken by the particle  =T2=22sec=1sec∴ Magnitude of average velocity  =DisplacementTime=21m/s=2m/s

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