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Q.

A particle moves with uniform acceleration along a straight line AB. Its velocities at A and B are 2 m/s and 14 m/s, respectively. M is the mid-point of AB. The particle takes t1 seconds to go from A to M and t2 seconds to go from M to B. Then t2/t1 is

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a

1:1

b

2:1

c

1:2

d

3:1

answer is C.

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Detailed Solution

v2=22+2as2⇒v2−4=as .....(i)142−v2=2as2⇒196−v2=as .....(ii)From (i) and (ii),v2−4=196−v2⇒v=10m/s Now t1=v−2a=10−2a=8at2=14−va=14−10a=4a⇒t2t1=4/a8/a=12

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