A particle moves with a velocity 6 i-4j+3k m/s under the influence of a constant force F = 20 i+ 15j -5 k newton. The instantaneous power applied to the particle is
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a
35 J/s
b
45 J/s
c
25 J/s
d
195 J/s
answer is B.
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Detailed Solution
Power P = F.v∴P=(20i+15j−5k)⋅(6i−4j+3k)=(20×6)−(15×4)−(5×3)=45J/s