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Q.

A particle moves with a velocity 6 i-4j+3k m/s under the influence of a constant force F = 20 i+ 15j -5 k newton. The instantaneous power applied to the particle is

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a

35 J/s

b

45 J/s

c

25 J/s

d

195 J/s

answer is B.

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Detailed Solution

Power P = F.v∴P=(20i+15j−5k)⋅(6i−4j+3k)=(20×6)−(15×4)−(5×3)=45J/s
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