Download the app

Questions  

A particle moves in the XY-plane according to the law x=kt,y=kt(1-αt), where k and α are positive constants and t is time. The trajectory of the particle is

a
y = kx
b
y = x - αx2k
c
y =  - ax2k
d
y = αx

detailed solution

Correct option is C

∵ x=kt⇒t=xkNow, y=kxk1-α·xkor  y=x-αx2k

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A ball is thrown with a velocity of u making an angle θ with the horizontal. Its velocity vector normal to initial vector (u) after a time interval of


phone icon
whats app icon