A particle moves in the x-y plane under the action of force F→ such that the value of its linear momentum P→ at any time t is Px=2cost , Py=2sint . The angle θ between F→ and P→ at a given time t will be
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a
900
b
00
c
1800
d
300
answer is A.
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Detailed Solution
P→=2[(cost)i^+(sint)j^] F→=dp→dt=2[(−sint)i^+(cost)j^] From above F→.P→=0 ⇒ angle between F→ and P→ is 900 or π2