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A particle moves in the x-y plane under the action of force $\vec{F}$ such that the value of its linear momentum $\vec{P}$ at any time t is $P_{x} = 2 \cos t$ , $P_{y} = 2 \sin t$ . The angle $θ$ between $\vec{F}$ and $\vec{P}$ at a given time t will be

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Correct option is A

P→=2[(cost)i^+(sint)j^] F→=dp→dt=2[(−sint)i^+(cost)j^] From above F→.P→=0 ⇒ angle between F→ and P→ is 900 or π2

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A particle moves in the x-y plane under the action of force F→ such that the value of its linear momentum P→ at any time t is Px=2cost , Py=2sint . The angle θ between F→ and P→ at a given time t will be

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Ready to Test Your Skills?

free study material

A particle moves in the x-y plane under the action of force $\vec{F}$ such that the value of its linear momentum $\vec{P}$ at any time t is $P_{x} = 2 \cos t$ , $P_{y} = 2 \sin t$ . The angle $θ$ between $\vec{F}$ and $\vec{P}$ at a given time t will be