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A particle moves in the X-Y plane under the influence of a force $\vec{F}$ such that its instantaneous momentum is $\vec{p} = \hat{i} 2 \cos t + \hat{j} 2 \sin t$ . What is the angle between the force and instantaneous momentum ?

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detailed solution

Correct option is C

F→=dp→dt=−i^2sint+j^2cott Hence F→.p→=0 , hence angle between F→ and p→ is 900

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A particle moves in the X-Y plane under the influence of a force F→ such that its instantaneous momentum is p→=i^2cost+j^2sint . What is the angle between the force and instantaneous momentum ?

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A particle moves in the X-Y plane under the influence of a force $\vec{F}$ such that its instantaneous momentum is $\vec{p} = \hat{i} 2 \cos t + \hat{j} 2 \sin t$ . What is the angle between the force and instantaneous momentum ?