A particle moves in the X-Y plane under the influence of a force F→ such that its instantaneous momentum is p→=i^2cost+j^2sint . What is the angle between the force and instantaneous momentum ?
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a
00
b
450
c
900
d
1800
answer is C.
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Detailed Solution
F→=dp→dt=−i^2sint+j^2cott Hence F→.p→=0 , hence angle between F→ and p→ is 900