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Q.

A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are px=2 cos t, py=2 sin t. The angle between F and p at time t is

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a

90°

b

0°

c

180°

d

30°

answer is A.

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Detailed Solution

Given that p→=pxi^+pyj^=2cost i^+2sint j^∴F→=dp→dt=−2sint i^+2cost j^Now,F→.p→=0 i.e. angle between F→ and p→ is 90o.

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