A particle moves in the $$xy-plane$$ under the action of a force F such that the components of its linear momentum p at any time t are px $$=$$ $$2$$ $$cos$$ t, py $$=$$ $$2$$ $$sin$$ t. The angle between F and p at time t is

Question

A particle moves in the $$xy-plane$$ under the action of a force F such that the components of its linear momentum p at any time t are px $$=$$ $$2$$ $$cos$$ t, py $$=$$ $$2$$ $$sin$$ t.  The angle between F and p at time t is

Infinity Learn · Accepted Answer

Given that p→ $$=$$ pxi⏞$$+py$$ j⏞    $$=$$ $$2$$ cost i⏞$$+2$$ sint j⏞F→ $$=$$ dp→$$dt=$$ $$-$$ $$sin$$ t i⏞$$+$$ $$2$$ $$cos$$ t j⏞Now, F→.p→ $$=$$ $$0$$   i.e. angle between  F→ and P→ is $$900$$.

A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are $p_{x} = 2 \cos t, p_{y} = 2 \sin t$ . The angle between F and p at time t is

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A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are px = 2 cos t, py = 2 sin t. The angle between F and p at time t is

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A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are $p_{x} = 2 \cos t, p_{y} = 2 \sin t$ . The angle between F and p at time t is