A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are px = 2 cos t, py = 2 sin t. The angle between F and p at time t is
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a
900
b
00
c
1800
d
300
answer is A.
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Detailed Solution
Given that p→ = pxi⏞+py j⏞ = 2 cost i⏞+2 sint j⏞F→ = dp→dt= - sin t i⏞+ 2 cos t j⏞Now, F→.p→ = 0 i.e. angle between F→ and P→ is 900.