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Q.

A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are px=2cos⁡t,py=2sin⁡t. The anglebetween F and p at time t is

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a

90∘

b

0∘

c

180∘

d

30∘

answer is A.

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Detailed Solution

Given that p→=pxi^+pyj^=2cos⁡ti^+2sin⁡tj^∴ F→=dp→dt=−2sin⁡ti^+2cos⁡tj^ Now, F→⋅p→=0 i.e. angle between F→ and p→ is 90∘

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