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Questions  

A particle moves in the xy-plane under the action of a force F such that the components of its linear momentum p at any time t are px=2cost,py=2sint. The angle
between F and p at time t is 

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a
90∘
b
0∘
c
180∘
d
30∘

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detailed solution

Correct option is A

Given that p→=pxi^+pyj^=2cos⁡ti^+2sin⁡tj^∴ F→=dp→dt=−2sin⁡ti^+2cos⁡tj^ Now, F→⋅p→=0 i.e. angle between F→ and p→ is 90∘


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