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Q.

A particle is moving along a circular path of radius 6 m with a uniform speed of 8 m/s. The average acceleration when the particle complete one half of the revolution is

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a

163π  m/s2

b

323π  m/s2

c

643π  m/s2

d

42π  m/s2

answer is C.

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Detailed Solution

t=π×68  sec = 3π4 sec.After half revolution velocity is reversed.∴   aavg.  =  Δv→t=8−−83π/4=643π  m/s2
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