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A particle is moving along a circular path of radius 6 m with a uniform speed of 8 m/s. The average acceleration when the particle complete one half of the revolution is

a
163π  m/s2
b
323π  m/s2
c
643π  m/s2
d
42π  m/s2

detailed solution

Correct option is C

t=π×68  sec = 3π4 sec.After half revolution velocity is reversed.∴   aavg.  =  Δv→t=8−−83π/4=643π  m/s2

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