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Questions  

A particle is moving along the path given by  y=Ct6   (where C is a positive constant). The relation between the acceleration ‘a’ and the velocity (v) of the particle at t=5  is

a
5a=v
b
v=5a
c
a =v
d
a=v

detailed solution

Correct option is D

velocity v=6ct5---1acceleration a=30Ct4-----2dividing we get va=t5   if t=5,  v=a

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