A particle moving along a straight line has a velocity vms-1, when it has cleared a distance y meter. These two are connected by the relation v=49+y. When its velocity is 1ms-1, its acceleration(in ms-2) is

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1/2

answer is D.

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Detailed Solution

v=49+y v2=49+y=U2+2ayComparing 2a = 1 a = 1/2 = constant

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