A particle is moving along a straight line and its velocity at time t is given by v = 2t m/s. If its instantaneous acceleration at t = 2 sec is ‘a’ and average acceleration in the interval t = 0 to t = 4 sec is b , then

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a = b = 4 m/s2a>\bar{a}

a =4 m/s2 , b = 2 m/s2

a=b = 2 m/s2

a = 2 m/s2, b = 4 m/s2

answer is C.

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Detailed Solution

Instantaneous acceleration a = dvdt = 2 m/s2 Since instantaneous acceleration is constant , average acceleration = 2 m/s2

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