First slide

Work done by Diff type of forces

Question

A particle is moving along a straight line under the action of a force. Its kinetic energy varies with time as KE = 7t. Force acting on the particle :

Easy

A

is increasing with time
B

is decreasing with time
C

is constant
D

is zero

Solution

$\frac{1}{2} {mv}^{2} = 7 t \Rightarrow v \propto t^{1 / 2} \Rightarrow \frac{dv}{dt} \propto t^{- 1 / 2}$ which is decreasing with time.

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