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A particle is moving along a straight line with an acceleration a = 3t2 m/s2 where ‘t’ is time in second. Initial velocity of the particle is zero. Then the displacement of the particle at t = 2 sec is

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a

b

c

12 m

d

answer is A.

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Detailed Solution

dvdt=3t2 ⇒∫0vdv = ∫0t3t2dt ⇒v = t3 Therefore dxdt=v=t3 ⇒∫0xdx = ∫02t3dt ⇒x = 4 m .

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