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Questions  

A particle moving along X-axis has acceleration ‘f’ at time ‘t’ given by f=f01-tT where f0, T are constants. The particle at t = 0 has zero velocity. In the time interval between t = 0 and the instant when f = 0, the particle velocity v0 is

a
12f0T2
b
f0T2
c
12f0T
d
f0T

detailed solution

Correct option is C

at t=0 , v=0 acceleration f = f01-1TAt f=0; t=Tf=dvdt∫0vxdv=∫t=0t=Tfdt Solving we  get 12f0T

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