A particle is moving along x-axis and its position is given by x=2cos24πt cm. Then
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a
The particle does not execute simple harmonic motion
b
The particle executes simple harmonic motion about the point x = 1 cm
c
amplitude of oscillation of the particle is 1 cm
d
both (2) and (3) are right
answer is D.
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Detailed Solution
x=2cos24πt=1+cos8πtFrom this equation it is evident that equilibrium position of the particle is at x = 1 cm (point A). Amplitude of oscillation is 1cm. Origin O and point B are extreme positions of the particle.