First slide

The 3 equation for uniform acc

Question

Particle A is moving along X-axis. At time t = 0, it has velocity of $10 {ms}^{- 1}$ and acceleration $- 4 {ms}^{- 2}$ . Particle B has velocity of $20 {ms}^{- 1}$ and acceleration $- 2 {ms}^{- 2}$ . Initially both the particles are at origin. At time t = 2 s, distance between the two particles is

Moderate

A

24 m
B

36 m
C

20 m
D

42 m

Solution

At $t = 2 s; x_{A} = 10 \times 2 - \frac{1}{2} \times 4 \times (2)^{2} = 12 m$
and $x_{B} = 20 \times 2 - \frac{1}{2} \times 2 \times (2)^{2} = 36 m$

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