A particle is moving along x-axis under the action of a conservative force and its potential energy at a distance x from the origin is given by U=(8-3x+x2) J . Then the work done by an external agent in moving the particle from x = 0 to x = 2 m is

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answer is 3.

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Detailed Solution

W=Uf-Ui=(8-3(2)+22)-(8-3(0)+0) J=-2 J

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