A particle is moving along the x-axis whose position is given by x=4−9t+t33. Mark the correct statement(s) in relation to its motion.

v=dxdt=−9+t2=0⇒t=3sa=dvdt=2tThe particle's velocity is getting zero at t = 3 s, where it changes its direction of motion. For 0 < t < 3 s, v is negative, a is positive, so particle is slowing down. For t > 3 s, both v and a are positive, so the particle is speeding up.