First slide

Ray optics

Question

A particle is moving along x-axis with 4 m/sec in-front of plane mirror, which is moving along negative direction with 2 m/sec. speed of image with respect to ground will be

Moderate

A

6 m/sec
B

4 m/sec
C

8 m/sec
D

2 m/sec

Solution

${\vec{V}}_{O / m} = - {\vec{V}}_{I / m}$
${\vec{V}}_{O / m} = {\vec{V}}_{O / g} - {\vec{V}}_{m / g} = 4 + 2$ = 6 m/sec
$\begin{aligned} {\vec{V}}_{I / m} = {\vec{V}}_{I / g} - {\vec{V}}_{m / g} \\ - 6 = {\vec{V}}_{I / g} - (- 2) \end{aligned}$
${\vec{V}}_{I / g} = - 8 m / s e c$ (negative sign shows its velocity along negative x-axis) So, correct answer will be (c).

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