A particle is moving in a circular path. If its kinetic energy is doubled, keeping its angular momentum unchanged, then new angular velocity of rotation is ______
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a
ω2
b
2ω
c
4ω
d
ω4
answer is B.
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Detailed Solution
L=mωr2 and k=12mω2r2=12Lω∴ 12Lω'=2k=212Lω ⇒ ω'=2ω.