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Q.

A particle is moving on a circular path of radius r with uniform speed v. What is the displacement of the particle after it has described an angle of 600'?

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a

r2

b

r3

c

r

d

2r

answer is C.

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Detailed Solution

According to cosine formulacos 600 = r2+r2-x22r2∴  x = r2r2 cos 600 = 2r2-x2x2 = 2r2-2r2cos 600       = 2r2[1-cos 600]       = 2r2[2 sin2 300] = r2∴x = r
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