A particle moving in a straight line covers half the distance with Speed Vo.The other half of the distance is covered in two equal time intervals with speed V1andV2respectively. The average speed of the particle during this motion is
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a
Vo(V1+V2)Vo+V1+V2
b
2Vo(V1+V2)Vo+V1+V2
c
2Vo(V1+V2)2Vo+V1+V2
d
Vo(V1+V2)2Vo+V1+V2
answer is C.
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Detailed Solution
A to B :→given velocity =V0; for distance=d2 time t=distancevelocity t = (d2)V0 = d2V0---(1)B to D :→if time taken for next distance= d2 let time taken for d2 be t0 for a time of t02 velocity= V1; and remainig time of t02 velocity= V2 for distan BD→ d2 = V1 t02 + V2 t02 t0 = d(V1+V2)----(2) Average Speed=total distancetotal time Average Speed=dt+t0 substitute eqn(1) and(2) Average Speed = 2V0(V1+V2)2V0+(V1+V2)