A particle moving in a straight line covers half the distance with Speed $V_o$.The other half of the distance is covered in two equal time intervals with speed $V_1$and$V_2$respectively. The average speed of the particle during this motion is

detailed solution

Correct option is C

A  to  B    :→given velocity =V0; for distance=d2 time t=distancevelocity       t  =   (d2)V0    =    d2V0---(1)B  to  D    :→if time taken for next distance=    d2 let time taken for     d2 be t0 for a time of t02 velocity=   V1; and remainig time of t02 velocity=   V2 for distan BD→    d2   =    V1  t02   +  V2  t02                    t0     =     d(V1+V2)----(2)   Average Speed=total distancetotal time Average Speed=dt+t0  substitute eqn(1) and(2) Average Speed    =     2V0(V1+V2)2V0+(V1+V2)