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A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance is covered in two equal time intervals with speed of 4.5 m/s and 7.5 m/s respectively. The average speed of the particle during this motion is :

a
4.0 m/s
b
5.0 m/s
c
5.5 m/s
d
4.8 m/s

detailed solution

Correct option is A

t1 = x23 = x6, x1 = 4.5t2, x2 = 7.5t2Also x1+x2 = x2= (4.5+7.5)t2That is t2 = x24Total time t = t1 + 2t2 = x6+2x24 = x4vavg = xt = 4 m/s

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