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Q.

For a particle moving in a straight line, the displacement s depends on time t as t=αt3+βt2+γt+δ. The ratio of its initial acceleration to its initial velocity is

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a

α/2β

b

γ/2β

c

2β/γ

d

2β/α

answer is C.

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Detailed Solution

Given that, s=αt3+βt2+γt+δNow, v=dsdt=3αt2+2βt+γ.....(1)and a=dvdt=6αt+2β....(2)At time t = 0, From eq. (1), v=γFrom eq. (ii), a=2β∴aVt=0=2βγ
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