Particle moving in a straight line is shown in fig. Corresponding acceleration versus velocity graph will be

acceleration a=dvdt                          =dvdsdsdt=dvds.V………..(1) ∵dsdt=VFrom given graphdvds=1010=1S−1∴ From Equation ……..(1)   a=1×V⇒a=V  Therefore acceleration versus velocity graph will be a straight line passing through origin with slope 1S-1.