Q.

A particle is moving in a straight line with initial velocity u and uniform acceleration f. If the sum of the distances travelled in tth and (t+1)th seconds is 100 cm, then its velocity after t seconds, in cm/s,  is

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a

20

b

30

c

50

d

80

answer is C.

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Detailed Solution

Sum of distances travelled in tth and (t+1)th seconds is 100 cm.u+a2(2t-1)+u+a2(2(t+1)-1) = 1002u + 2at = 100u+at = 1002    ⇒v = 50 cm/s
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