A particle is moving in a straight line with retardation proportional to its displacement. Its loss of K.E for any displacement x is proportional to
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a
x2
b
ex
c
x
d
log ex
answer is A.
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Detailed Solution
Given retardation α displacement ∴ dvdt α x ⇒ dvdt = K x k is proportionlity constant ∴ dvdx ⋅ dxdt= K ⋅x dvdx ⋅ V= K ⋅x V d V = K⋅x⋅ dx v1v2∫vdv = K⋅ ax∫xdx ∴ v222−v122 = K⋅ x22 mv222−mv122 = K⋅m2 x2 K.E2 − K.E1 = mKα ⋅ x2 ∴ loss of K.E α x2