Questions
A particle moving with constant acceleration covers a distance of 20m in 3rd sec and 40m in 5th sec. What is acceleration of the particle?
detailed solution
Correct option is D
Distance covered in nth sec Sn=U+an−12 here initial velocity=U;acceleration=aIn3rd sec Distance covered S3=U+a3−12⇒20=U+5a2………..(1) In 5th sec Distance covered S5=U+a5−12⇒40=U+9a2……....(2)subtract equation(2)−(1)⇒40−20=9a2−5a2⇒20=a2(9−5)⇒20=a2(4)⇒a=10m/s2Talk to our academic expert!
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A particle is moving along the x-axis whose acceleration is given by , where x is the location of the particle. At t = 0, the particle is at rest at x = 4/3 m. The distance travelled by the particle in 5 s is
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