A particle is moving with constant acceleration from A to B in a straight line AB. If U and V are the velocities of particle at A and B respectively, then its velocity of particle at the midpoint C will be
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a
(U2+V22)2
b
U2+V22
c
V−U2
d
U2+V22
answer is D.
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Detailed Solution
let c be the mid point of AB, let velocity at c be x from A to C; initial velocity =u; final velocity =x; distance =d2;acceleration =a substitute in v2=u2+2as---(1) X2 = U2 + 2a⋅d2 → -- (2) from A to B; initial velocity =u; final velocity =v; distance =d;acceleration =a substitute in equation (1) v2=u2+2ad ⇒ad= v2-u22---(3) substitute equation (3) in (2) X2 = U2 + v2-u22 X= v2+u22=velocity of the particle at mid point of AB