A particle is moving with uniform acceleration along a straight line ABC. Its velocity of at A and C are 5 m/s 25 m/s respectively. If BC - 2 AB, find the ratio of time of travel from A to B to that from B to C

See figure v2=u2+2as or v2−25=2as....(1)and (25)2=v2+4asor 625 -  v2 = 4 as ..(2)Dividing eq. (1) by eq. (2), we getv2−25625−v2=12 or 2v2−50=625−v2or 3 v2 =675 or v2 =  225 or V = 15 m/sFor uniform acceleration, [(v - u) / t]should be constant.∴15−5t1=25−15t2 or 10t1=10t2or t1t2=11