A particle moving with a uniform acceleration along a straight line covers distances a and b in successive intervals of p and q second. The acceleration of the particle is:
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a
pqp+q2 (bp - aq)
b
2(aq-bp)pq(p-q)
c
bp-aqpq(p-q)
d
2bp-aqpq(p+q)
answer is D.
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Detailed Solution
Let initial velocity = u and acceleration = AThen a=up+12Ap2and a+b=u(p+q)+12Ap+q2By solving above equation A=2bp-aqpq(p+q)