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Q.

A particle moving with a uniform acceleration travels 24 m and 64 m in the first two consecutive intervals of 4 sec each. Its initial velocity is

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a

1 m/sec

b

10 m/sec

c

5 m/sec

d

2 m/sec

answer is A.

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Detailed Solution

Distance travelled in 4 sec24=4u+12a×16.....(i)Distance travelled in total 8 sec88=8u+12a×64...(ii)After solving (i) and (ii), we get u = 1 m/s.
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