A particle is moving with uniform speed along the circumference of a circle of radius R under the action of a central fictitious force F which is inversely proportional to R3. Its time period of revolution will be given by:
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a
T ∝ R52
b
T ∝ R32
c
T ∝ R2
d
T ∝ R43
answer is C.
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Detailed Solution
Fictitous force is providing centripetal force. ⇒mRω2=F=KR3⇒ω2∝R−4⇒T2∝R4⇒T∝R2