A particle is moving with uniform speed along the circumference of a circle of radius R under the action of a central fictitious force F which is inversely proportional to R3. Its time period of revolution will be given by:

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T ∝ R52

T ∝ R32

T ∝ R2

T ∝ R43

answer is C.

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Detailed Solution

Fictitous force is providing centripetal force. ⇒mRω2=F=KR3⇒ω2∝R−4⇒T2∝R4⇒T∝R2

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