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Q.

A particle is moving with velocity V¯=i^+3j^ and it produces an electric field at a point given by E→=2k^ . It will produce magnetic field at that point equal to (all quantities are in S.I units)

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a

6i^−2j^μoε0

b

6i^+2j^μoε0

c

zero

d

cannot be determined from the given data

answer is A.

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Detailed Solution

E→=14πε0qr2r^=2k^ ∴We can say that direction of r→ is along k^ and 14πε0qr2=2  Now, as per Biot-Savart Law B→=μ04πqv→×r→r2=μ0ε0q4πε0r2i^+3j^×k^ =μ0ε02−j^+3i^ =6i^−2j^μ0ε0
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