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Q.

A particle is moving with velocity v→=i^+3j^ and it produces an electric field at a point given by E→=2k^. It will produce magnetic field at that point equal to (all quantities are in SI units)

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a

(6i^-2j^)μ0ε0

b

(6i^+2j^)μ0ε0

c

zero

d

cannot be determined from the given data

answer is A.

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Detailed Solution

E→=14πεoqr2r^=2k^,r^=k^ B→=μ04πqv→×r^r2=μ0ε0q4πε0r2(i^+3j^)×k^ =μ0ε02[-j^+3i^]=(6i^-2j^)μ0ε0
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