Q.
A particle is moving with velocity v→=i^+3j^ and it produces an electric field at a point given by E→=2k^ . It will produce magnetic field at that point equal to (all quantities are in SI units)
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a
(6i^−2j^)μ0ε0
b
(6i^+2j^)μ0ε0
c
zero
d
cannot be determined from the given data
answer is A.
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Detailed Solution
E→=q4πε0r2k^=2k^B→=μ02πqv→r2r^=μ0ε0q4πε0r2i^+3j^×k^
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