A particle is moving with a velocity of v→=(3 i^+4t j^) m/s. Find the ratio of tangential acceleration to that of normal acceleration at t = 1 sec.

At t=1s,v→=(3i^+4j^)m/s⇒v=32+42=5m/sNormal acceleration, an=v2RTotal acceleration, a→=dv→dt=4j^The direction of tangential acceleration should be along its velocity at=4cos⁡37∘=165,aN=a2-at2=125⇒ataN=1612=43