A particle is moving with a velocity v→=kyi^+xj^ where k is constant. The general equation for its path is
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a
y=x2+ constant
b
y2=x2+ constant
c
y2=x+ constant
d
xy=constant
answer is B.
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Detailed Solution
v→=kyi^+xj^ ⇒vxi+vyj=kyi^+xj^ ⇒dxdti+dydtj=kyi^+xj^ comparing, ⇒dxdt=ky; dydt=kx divide one by the other above equations dxdtdydt=kykx ⇒dxdy=yx ⇒xdx=ydy integrating ∫xdx=∫ydy ⇒y2=x2+c