A particle is moving, with a velocity of v=3+6t+9t2cms−1 The displacement of the particle in the interval t = 5 to t = 8 sec is

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1352 cm

1287 cm

1182 cm

11000 cm

answer is B.

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Detailed Solution

Given, v=3+6t+9t2cms−1 Or dsdt=3+6t+9t2 or ds=3+6t+9t2dt∴∫0s ds=∫58 3+6t+9t2dt∴s=3t+3t2+3t358 or s = 1287 cm

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