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Q.

A particle is moving on x-axis has potential energy U=2−20x+5x2 joules along x-axis. The particle is released at x=−3. The maximum value of ‘x’ will be [x is in meters and U is in joules]:

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a

5 m

b

3 m

c

7 m

d

8 m

answer is C.

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Detailed Solution

U=2−20x+5x2F=−dudx=20−10x[F∝−x⇒SHM]At equilibrium F = 020−10x=0x = 2 [mean position]since particle is released at x=−3, therefore amplitude of particle is 5
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