A particle is moving on x-axis such that its position varies with time(t) asx=(t−2)(t−4) : , where ‘t’ is in second and x is in meter. Let Sab denotes the distances travelled by the particle in the time intervalt = a to t = b . Then find the ratio of magnitudes S12S34=3 .
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answer is 3.
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Detailed Solution
x= (t-2) (t-4)x=t2-6t+8 v=dxdt=2t-6 and at t=0 velocity= u=-6 ms-1 a=dvdt= 2 ms-2 so s12=s2= u +a(n-12)=-6+22-12=-3 m s34=-6+2(4-12)=1m s12s34=3