A particle is moving in the x-y plane. At certain instant of time, the components of its velocity and acceleration are as follows: vx=3 ms−1, vy=4 ms−1, ax=2 ms−2 and ay=1 ms−2. The rate of change of speed at this moment is
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a
10ms−2
b
4ms−2
c
5ms−2
d
2ms−2
answer is D.
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Detailed Solution
Speed, v=vx2+vy2Rate of change of speed,dvdt=2vxdvxdt+2vydvydt2vx2+vy2=vxax+vyayvx2+vy2=3×2+4×19+16=105=2 ms−2