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A particle is moving in xy plane and equation of its trajectory is where x and y are in metre. When the distance of the particle from x-axis is maximum, speed of the particle is
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a
2 m/s
b
1 m/s
c
0.5 m/s
d
1.5 m/s
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Correct option is B
When distance from x-axis is maximum, velocity component along y-axis must be zero. i.e. dydt=0 i.e. 120−3×2xdxdt=0⇒dxdt=20xAgain, when y is maximum, dydx=0⇒120−6x=0⇒x=20 m∴ dxdt=2020m/s=1 m/sSimilar Questions
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