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Q.

A particle is moving in XY-plane such that x=b(2t+sin⁡2t),y=b(1−cos⁡2t)

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a

The acceleration of particle is constant

b

The acceleration of the particle is variable

c

The direction of motion of the particle makes π4 angle with X-axis at t=π4

d

The direction of motion of the particle make π4 angle with X-axis at = 1s

answer is A.

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Detailed Solution

(1) ∵x=b(2t+sin⁡2t)or vx=dxdt=2b+2bcos⁡2tor ax=dvdt=−4bsin⁡2t∵y=b(1−cos⁡2t)or vy=2bsin⁡2tor ay=dvydt=4bcos⁡2t∴a=ax2+ay2=4b(3) tan⁡θ=vyvx=2bsin⁡2t2b+2bcos⁡2t=sin 2t2 cos2 t=2 sin t cos t2 cos2 t=tan t At t=π4, θ=π4
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A particle is moving in XY-plane such that x=b(2t+sin⁡2t),y=b(1−cos⁡2t)