A particle is moving in XY-plane such that x=b(2t+sin2t),y=b(1−cos2t)
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a
The acceleration of particle is constant
b
The acceleration of the particle is variable
c
The direction of motion of the particle makes π4 angle with X-axis at t=π4
d
The direction of motion of the particle make π4 angle with X-axis at = 1s
answer is A.
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Detailed Solution
(1) ∵x=b(2t+sin2t)or vx=dxdt=2b+2bcos2tor ax=dvdt=−4bsin2t∵y=b(1−cos2t)or vy=2bsin2tor ay=dvydt=4bcos2t∴a=ax2+ay2=4b(3) tanθ=vyvx=2bsin2t2b+2bcos2t=sin 2t2 cos2 t=2 sin t cos t2 cos2 t=tan t At t=π4, θ=π4