A particle is moving in xy-plane with y=x/2 and vx=4−2t. Choose the correct options.
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a
Initial velocities in x and y directions are negative.
b
Initial velocities in x and y directions are positive.
c
Motion is first retarded, then accelerated.
d
Motion is first accelerated, then retarded.
answer is B.
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Detailed Solution
y=x2 implies that the particle is moving in a straight line passing through the origin. vx=4−2t,vx=ux+axt ux=4,ax=−2Now, y=x2⇒ dydt=12dxdt vy=12vx=2−t,vy=uy+ayt uy=2 and ay=−1