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Q.

A particle is moving in xy-plane with y=x/2 and vx=4−2t. Choose the correct options.

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a

Initial velocities in x and y directions are negative.

b

Initial velocities in x and y directions are positive.

c

Motion is first retarded, then accelerated.

d

Motion is first accelerated, then retarded.

answer is B.

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Detailed Solution

y=x2 implies that the particle is moving in a straight line passing through the origin.          vx=4−2t,vx=ux+axt         ux=4,ax=−2Now, y=x2⇒ dydt=12dxdt          vy=12vx=2−t,vy=uy+ayt          uy=2  and  ay=−1
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